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Hiking up a mountain, you notice that the air temperature drop 10°C for every 1,00 meters in elevation. The temperature was at 68°F at 2,000 meters in altitude. If the hiker is now at altitude of 5,000 meters, what is the current temperature? Show your work.

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Answer:

you're given a *rate* of decrease and then the *extent* of the "cause". SO the rate is 10C/1000m (right? You understand why this is a rate? You go 1000m up, the temperature drops 10C. And it happens continually, bit by bit, as you climb. That's a rate!

But, you don't stop with climbing just 1000m: you climb 1000m twice *more*. So, how much has the temperature dropped in all, by the end?

You really should be able to put this together as 10C/1000m x 3000m = result. It will be in units of (degrees) C.

Now, finish the problem and get down the mountain, before you freeze (also, winds kick up more on mountains -- a double whammy).

Explanation:

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