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I NEED HELP ASAP (20 points!!)

2. Given quadrilateral DEFG with vertices D(-3,0), E(-5,4), F(-2,7) and (3,8), use the coordinate rule for a 270° rotation to find the images of the vertices.
Rule: (a,b) =( , )

D(-3,0) = D'( , )
E(-5, 4) = E'( , )
F(-2, 7) => F'( , )
G( 3, 8) = G'( , )
Graph the image D'E'F'G'

I NEED HELP ASAP (20 points!!) 2. Given quadrilateral DEFG with vertices D(-3,0), E-example-1
User Orokusaki
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1 Answer

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Answer:

Rule:(a,b)=(a,-b)

D(-3,0)=D'(-3,-0)

E(-5,4)=E'(-5,-4)

F(-2,7)F'(-2,-7)

G(3,8)=G'(3,-8)

User Jduv
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