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8 votes
8 votes
Sin thetha + cos thetha upon sec thetha + cosec thetha = sin thetha • cos thetha​

User Eli Collins
by
2.8k points

1 Answer

25 votes
25 votes

Answer:

steps below

Explanation:

sin θ + cos θ / sec θ + cosec θ

= (sin θ + cos θ) / (1/cos θ+1/sin θ)

= (sin θ + cos θ) / ((sin θ + cos θ)/sin θ*cos θ)

= sin θ * cos θ

User Tbxfreeware
by
3.1k points
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