Question

I have attached the problem in a picture below!​

Answer 1

A. The solution set is x = 5 or -7

Explanation:

`\sqrt[4]{ {x}^(2) + 2x } = \sqrt[4]{35} \\ {({x}^(2) + 2x) }^{ (1)/(4) } = {(35)}^{ (1)/(4) } \\ {x}^{ (1)/(2) } + {2x}^{ (1)/(4) } = {35}^{ (1)/(4) } \\ {x}^(2) + 2x = 35 \\ {x}^(2) + 2x - 35 = 0 \\ (x - 5)(x + 7) = 0 \\ x = 5 \: or \: - 7`

Therefore, the answer is A. as the solution is x = 5 or -7