Final answer:
To find the mass of 8010 atoms of Cl35, calculate the contribution of Cl35 using its percentage abundance and atomic mass. Then convert the mass from amu to grams using the molar mass of Cl35.
Step-by-step explanation:
To find the mass of 8010 atoms of Cl35, we need to first calculate the mass contribution of Cl35 using its percentage abundance and atomic mass. Chlorine-35 has an atomic mass of 34.969 amu and a percent abundance of 75.77%. We can calculate the contribution of Cl35 to the average relative atomic mass by multiplying its percentage abundance by its atomic mass:
Contribution of Cl-35 = (75.77/100) × 34.969 amu = 26.525 amu
Next, we convert the mass from amu to grams by using the molar mass of Cl35. One mole of Cl35 has a molar mass of 35.45 g. So, the mass of 8010 atoms of Cl35 in grams would be:
(26.525 amu / 1 mole) × (35.45 g / 1 mole) × 8010 atoms = 7.264 grams