Question

What is the average acceleration of an object that goes from rest to a

speed of 7m/s in just 0.1s?
91 POINTS!!!!!!!!

Answer 1

• Initial velocity=u=0m/s
• Final velocity=v=7m/s
• Time=t=0.1s

`\\ \sf\longmapsto Acceleration=(v-u)/(t)`

`\\ \sf\longmapsto Acceleration=(7-0)/(0.1)`

`\\ \sf\longmapsto Acceleration=(7)/(0.1)`

`\\ \sf\longmapsto Acceleration=70m/s^2`

Answer 2

Below!

Step-by-step explanation:

To calculate the average acceleration you can use this formula....

acceleration = finalvelocity - initial velocity / time

Because the object begins at rest we know that our initial velocity is 0 m/s

Our final velocity is 7 m/s, and our time is 0.1 seconds....

Plugging in our values :

acceleration = 7m/s - 0.1 m/s / 0.1 s

= 7 m/s / 0.1s

= 70 m/s^2

This is already at the proper amount of sig figs so we're good to go!

Therefore the average acceleration of this object is 70 m/s^2

Hope this helps! Best of luck <3