Question

Please help!!! giving 100 points for correct answer

(algebra 2)

|-3d-6|+|-5-d^2| for d =-3

please give a step by step too

Answer 1

17

Explanation:

Given expression:

`|-3d-6|+|-5-d^2|`

To evaluate for d = -3, substitute d = -3 into the expression:

`\implies |-3(-3)-6|+|-5-(-3)^2|`

`\textsf{Apply exponent rule} \quad a\cdot a=a^2:`

`\implies |(-3)^2-6|+|-5-(-3)^2|`

`\textsf{Apply exponent rule} \quad (-a)^2=a^2:`

`\implies |3^2-6|+|-5-3^2|`

`\implies |9-6|+|-5-9|`

Subtract the numbers:

`\implies |3|+|-14|`

`\textsf{Apply absolute rule} \quad |a|=a, \quad a\geq 0`

`\implies 3+|-14|`

`\textsf{Apply absolute rule} \quad |-a|=a, \quad a > 0`

`\implies 3+14`

Add the numbers:

`\implies 17`

Answer 2

17

Explanation:

`\sf |-3d-6|+|-5-d^2| \quad for\:\: d = -3`

Given expression:

`\sf |-3d-6|+|-5-d^2|`

substitute d = -3

`\sf |-3(-3)-6|+|-5-(-3)^2|`

simplify following inside parenthesis

`\sf |9-6|+|-5-9|`

simplify by combining integers

`\sf |3|+|-14|`

if |-a| or |a| then equals to a

`\sf 3+14`

evaluate:

`\sf 17`