Answer:
35.5 g of chlorine would be in the compound
Step-by-step explanation:
using the mole concept
first write down your balanced chemical equation
CaCl2_____Ca +Cl2
then if 40g of Ca____ 71 g of cl
so 20g of Ca_____Xg of cl
cross multiplying we have
X= (20 *71)/40 = 35.5g