Question

a line passes through the point (4 –6) and has a slope of -
`(5)/(4)`. which is the equation of the line

Answer 1

`y = (5)/(4)x - 1`

Explanation:

A line that passes through the point (4,-6) has a slope of 5/-4. Which of the following gives the equation of the line?

With the slope of 5/-4, and the ordered pair (4,-6) :

let m = 5/-4 (slope),

x1 = 4

y1 = -6

We can use those given values into the point-slope formula:

y - y1 = m(x - x1)

Plugging in those values will give you the answer:

y - (-6) =
`(5)/(-4)` (x - 4)

Distribute
`(5)/(-4)` into the terms inside the parenthesis:

y + 6 =
`( 5)/(-4)x` + 5

Subtract 6 from both sides to isolate y:

y + 6 - 6 =
`-( 5)/(4)x` +5 - 6

The equation of the line in slope-intercept form is:

`y = -( 5)/(4)x - 1`