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3 votes
3 votes
Can someone PLEASE HELP ME ON NUMBER 10 ONLY PLEASE ITS MY LAST QUESTION ILL GIVE YOU BEAINLIEST AND PTS

Can someone PLEASE HELP ME ON NUMBER 10 ONLY PLEASE ITS MY LAST QUESTION ILL GIVE-example-1
User Misterzik
by
2.9k points

1 Answer

14 votes
14 votes

Answer:

Explanation:

XB bisects ∠AXC.

⇒ ∠AXB = ∠BXC = 6x + 40

∠AXB + ∠BXC = ∠AXC

6x + 40 + 6x + 40 = 7x + 100

6x + 6x + 40 + 40 = 7x + 100

Add like terms

12x + 80 = 7x +100

Subtract 80 from both sides

12x = 7x + 100 -80

12x = 7x + 20

Subtract 7x form both sides

12x - 7x = 20

5x = 20

Divide both sides by 5

x = 20/5

x = 4

∠AXC = 7x + 100

= 7*4 + 100

= 28 + 100

∠AXC = 128

User Dmitry  Yaremenko
by
3.2k points
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