Question

Tan thetha + cot thetha = cosec thetha • sec thetha
​

Answer 1

see explanation

Explanation:

Using the identities

tan x =
`(sinx)/(cosx)` , cot x =
`(cosx)/(sinx)` , cosec x =
`(1)/(sinx)` , sec x =
`(1)/(cosx)`

Consider the left side

tanθ + cotθ

=
`(sin0)/(cos0)` +
`(cos0)/(sin0)`

=
`(sin^20+cos^20)/(sin0cos0)`

=
`(1)/(sin0cos0)`

=
`(1)/(sin0)` ×
`(1)/(cos0)`

= cosecθ × secθ

= right side , thus verified