Question

Question 8

A compound has an empirical formula of C3H4O and a formula mass of 168 g/mol. What is the compound’s molecular formula?

Answer 1

C9H12O3

Step-by-step explanation:

(EF)n=MF

(C3H4O)n=168

[(12×3)+(1×4)+(16×1)]n=168

[36+4+16]n=168

56n=168

n=3

MF=(C3H4O)3

MF=C9H12O3