117,975 views
31 votes
31 votes
Find the 8th term of the geometric sequence whose common ratio is 2/3 and whose first term is 7​

User Metter
by
2.9k points

1 Answer

29 votes
29 votes

Answer:

The 8th term of the sequence is 896/2187.

Explanation:

We want to find the 8th term of a geometric sequence whose common ratio is 2/3 and whose first term is 7.

We can write a direct formula. Recall that the direct formula of a geometric sequence is given by:


\displaystyle x_(n) = a\left(r\right)^(n-1)

Where a is the initial term and r is the common ratio.

Substitute:


\displaystyle x_(n) = 7\left((2)/(3)\right)^(n-1)

To find the 8th term, let n = 8. Substitute and evaluate:


\displaystyle \begin{aligned} x_(8) &= 7\left((2)/(3)\right)^((8) - 1) \\ \\ &= 7\left((2)/(3)\right)^(7) \\ \\ &= 7\left((128)/(2187)\right) \\ \\ &= (896)/(2187) = 0.4096...\end{aligned}

In conclusion, the 8th term of the sequence is 896/2187.

User MrZander
by
2.6k points