Question

Please help!! second time posting !! algebra question, about functions!

how do you inverse/isolate y in this question, “f(x) = x-3/x” or y = x-3/x

I know it becomes y=x-3/x, then becomes x = y-3/y,
(By the way, the bottom denominator y is over y-3),

I know the answer is f^-1(x) = 3/1-x, I just don’t understand how you isolate y in this specific question, thank you so much!!

Answer 1

steps below

Explanation:

y = (x-3) / x

replace x and y: x = (y-3) / y

y - 3 = xy

y - xy = 3

y(1 - x) = 3

y (f'(x)) = 3 / (1-x)