Question

A cannonball is shot from a cannon at a launch angle of 63° and an initial velocity

of 147 m/s.The gravitational acceleration is -9.8 m/s2. Assuming NO air
resistance, how long will it take the cannonball to reach the peak of its trajectory?

Answer 1

13.4s

Step-by-step explanation:

time = usinx/g. (X= angle) , (u = initial velocity)

=( 147×sin63)/9.8

time= 13.4s