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Find all the values of a such that there is no value of b that satisfies the equations 2-b/3-b = 5a

User Rycha
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1 Answer

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Answer:


a = (2 - b)/(5(3 - b)) \: \: b = (15a - 2)/(5a - 1)

Explanation:

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1. \: ( (2 - b)/(3 - b) )/(5) = a \\ 2. (2 - b)/(5(3 - b)) = a \\ 3. \: a = (2 - b)/(5(3 - b)) \\ \\ \\ 1. \: 2 - b = 5a(3 - b) \\ 2. \: 2 - b = 15a - 5ab \\ 3. \: - b = 15a - 5ab - 2 \\ 4. \: - b + 5ab = 15a - 2 \\ 5. \: 5ab - b = 15a - 2 \\ 6. \: b(5a - 1) = 15a - 2 \\ 7. \: b = (15a - 2)/(5a - 1)

User KaMyLL
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