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The chance of picking at random a yellow ball from a bag containing 6 red balls and 2 yellow balls is:

A. ¼
B. ¾
C. 2
D. 1​

The chance of picking at random a yellow ball from a bag containing 6 red balls and-example-1

2 Answers

5 votes

Answer:

Explanation:

c sorry if im wrong

User Reederz
by
4.4k points
5 votes

Answer:

1/4.

Explanation:

If the bag contains a total of 8 balls, then the chance of picking 2 yellow balls from a total of 8 balls is given by 2/8, simplified, this is 1/4.

This is how you simplify:

1. Write the fraction.


(2)/(8)

2. Find a number that can divide both the numerator and the denominator. A number could be 2, therefore, divide both the numerator and the denominator by this number.


(2/2)/(8/2) =(1)/(4)

Final answer:
(1)/(4)

User Jezthomp
by
4.0k points