Solve Absolute Value.
|6x + 3| = 15
We know either 6x + 3 =15 or 6x + 3 = −15
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6x + 3 = 15 (Possibility 1)
6x + 3 - 3 = 15 − 3 (Subtract 3 from both sides)
6x = 12
![\boldsymbol{\sf{(6x)/(6)=(12)/(6) \ \longmapsto \ (Divide \ both \ sides \ by \ 6) }}](https://img.qammunity.org/2023/formulas/mathematics/college/744uwy74pp4ml6d50ekp9ielkpd1ijejts.png)
x = 2
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6x + 3 = −15 (Possibility 2)
6x + 3 - 3 = -15 - 3 (Subtract 3 from both sides)
6x = -18
![\boldsymbol{\sf{(6x)/(6)=(-18)/(6) \ \longmapsto \ (Divide \ both \ sides \ by \ 6) }}](https://img.qammunity.org/2023/formulas/mathematics/college/jaunk1n32merigzhc6urtb5pc2n1o2l58z.png)
x = -3
Therefore, the answer is x = 2 or x = −3. The correct option is alternative "D".