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3 votes
A rectangle has a length four more than

five times the width. If the perimeter is
32 units, find the width and length.

User Sambowry
by
7.0k points

1 Answer

4 votes
L ≥ 5w + 4
2(L+w) ≥ 32

L+w ≥ 16

6w + 4 ≥ 16
6w ≥ 12
w ≥ 2

L ≥ 5w + 4
L ≥ 14

If L = 14 and w = 2 then the perimeter is 32.
These are the smallest dimensions that fit the criteria.

Note: If we raise the width by 1 to w = 3
then the length is at least 19. At 19 by 3 we have P = 44
Like would be appreciated!!
User Myrtlecat
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6.2k points