Question

What is the equation in polnt-slope form of the line passing through (-2, 1) and (4, 13)? (1 point)

O a
y-1=-2(x – 4)
Ob
y- 1 = 2(x + 2)
ос
y - 13 = -2(x + 2)
Od
y - 13 = 2(x + 4)

Answer 1

b

Explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

Calculate m using the slope formula

m =
`(y_(2)-y_(1) )/(x_(2)-x_(1) )`

with (x₁, y₁ ) = (- 2, 1) and (x₂, y₂ ) = (4, 13)

m =
`(13-1)/(4-(-2))` =
`(12)/(4+2)` =
`(12)/(6)` = 2

Using the point (- 2, 1 )

y - 1 = 2(x - (- 2)) , that is

y - 1 = 2(x + 2) → b

Using the point (4, 13)

y - 13 = 2(x - 4) ← not one of the options