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1 vote
A coin bank contains nickels and dimes. The

number of dimes is 10 less than twice the
number of nickels. The total value of all
coins is $2.75. Find the number of each type
of coins in the bank. Show work

User Ole K
by
3.3k points

1 Answer

4 votes

Answer: 15 nickels and 20 dimes

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Work Shown:

n = number of nickels

d = number of dimes

d = 2n-10 since "number of dimes is 10 less than twice the number of nickels"

0.05n = value of all the nickels in dollars

0.10d = value of all the dimes in dollars

0.05n+0.10d = total value in dollars

0.05n+0.10d = 2.75

Multiply all three terms by 100 to move the decimal point over two spots to the right. We get this new updated equation

5n+10d = 275

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Now plug in d = 2n-10 and solve for n

5n+10d = 275

5n+10(2n-10) = 275

5n+20n-100 = 275

25n-100 = 275

25n = 275+100

25n = 375

n = 375/25

n = 15

There are 15 nickels.

Use this to find the value of d.

d = 2n-10

d = 2*15-10

d = 30-10

d = 20

There are 20 dimes.

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Check:

5n = 5*15 = 75 cents from just the nickels only

10d = 10*20 = 200 cents from just the dimes only

5n+10d = 75+200 = 275 cents total

275 cents = 275/100 = $2.75

This confirms the answers.

User Sprague
by
4.0k points