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10 votes
Let f(x)=4x^2-2
f(t+1)

User Kyle Lemons
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1 Answer

23 votes
23 votes

Answer:


f(x) = 4 {x}^(2) - 2 \\ f(t + 1) = 4 {(t + 1)}^(2) - 2 \\ = 4( t + 1)(t + 1) - 2 \\ = 4( {t}^(2) + 2t + 1) - 2 \\ = 4 {t}^(2) + 8t + 4 - 2 \\ = 4 {t}^(2) + 8t + 2

I hope I helped you^_^

User Manoj Lodhi
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