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25 votes
25 votes
The chef at a steakhouse has 350 pounds of sirloin steak on hand for Saturday night. If each portion is 10 ounces, how many sirloin steak dinners

can be served? Round to the nearest whole dinner. (There are 16 ounces in a pound.)
dinners

User Brody Robertson
by
3.2k points

2 Answers

13 votes
13 votes

Final answer:

After converting 350 pounds of sirloin steak to 5600 ounces (using the conversion rate of 1 pound = 16 ounces), we divide by the portion size of 10 ounces per dinner to find that the chef can serve 560 sirloin steak dinners.

Step-by-step explanation:

To determine how many sirloin steak dinners can be served, we first need to convert the total pounds of steak to ounces, since the portions are measured in ounces. The first step is to use the conversion rate: 1 pound = 16 ounces. Multiplying the number of pounds by 16 gives us the total number of ounces available.

350 pounds × 16 ounces/pound = 5600 ounces of sirloin steak on hand.

Next, we need to divide the total number of ounces of sirloin steak by the portion size, which is 10 ounces per dinner.

5600 ounces ÷ 10 ounces/dinner = 560 dinners.

Therefore, the chef can serve 560 sirloin steak dinners. The answer is rounded to the nearest whole number, as requested.

User Raja Manickam
by
2.6k points
21 votes
21 votes

Answer:

560 dinners

Step-by-step explanation:

First, find the amount of ounces by multiplying 350 pounds by 16 since every one pound is 16 ounces. 350×16=5600. That means there are 5600 ounces of meat. Therefore, to find the amount of steaks that can be served, divide 5600 divided by 10. 5600÷10=560.

User Andrew Grothe
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3.1k points