Question

Tìm x : 2x^2-7x+3=0
giúp tui zới, please

Answer 1

Solving Quadratic Equations with the Quadratic Formula

Answer:

`x = 3` and
`x = (1)/(2)\\`

Step-by-step Explanation:

Recall:

if we have a quadratic equation,
`ax^2 +bx +c = 0`, where
`a`,
`b` and
`c` are real numbers and
`a \\eq 0`,
`x = (-b \pm √(b^2 -4ac))/(2a)`.

Given:

`2x^2 -7x +3 = 0`

Solving for
`x`:

`x = (-(-7) \pm √((-7)^2 -4(2)(3)))/(2(2)) \\ x = (-(-7) \pm √(49 -4(2)(3)))/(2(2)) \\ x = (7 \pm √(49 -24))/(4) \\ x = (7 \pm √(25))/(4) \\ x = (7 \pm 5)/(4)`

Solving with the positive value:

`x = (7 +5)/(4) \\ x = (12)/(4) \\ x = 3`

Solving with the negative value:

`x = (7 -5)/(4) \\ x = (2)/(4) \\ x = (1)/(2)`