Answer:
6molO2 3/2O22Fe=4,5024molFe .
Step-by-step explanation:
You have to start with the balanced chemical equation. Iron is just Fe. Oxygen in nature is found as an O2 molecule.
2Fe(s)+3/2O2(g) Fe2O3(s)
If you check the balance. There are two Fe on both sides of the equation and three O on both sides, so it’s balanced.
Now use the stoichiometric ratios (the coefficients of the balanced chemical equation) to convert 6 mol of oxygen to iron.
6molO2 3/2O22Fe=4.5024molFe .
These coefficients can be used as conversion factors when it comes to substance moles.
Some of you may insist that a balanced chemical reaction must have whole numbers. This is not really necessary. The reaction I wrote above is a named type of reaction, called Fe2O3 formation. In this type of reaction, there must be a mole of product so that it requires that sometimes there are fractional numbers for the coefficients in the reagents.
But, just for the argument, let’s rebalance the equation for integer coefficients only.
4Fe(s)+3O2(g) 2Fe2O3(s)
We are now using the coefficients as conversion factors, as we have done before.