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Answer:
Explanation:
The sum of complementary angles is 90°.
∠ABD +∠BDC = 90°
(y -30)° +(2y)° = 90°
3y = 120 . . . . . . . . . . . . divide by °, add 30
y = 40 . . . . . . . . . . . divide by 3
∠ABD = (40 -30)° = 10°
∠BDC = 2(40)° = 80°