Explanation:
if we are taking in terms of domain.. is d set of number that we can put to the function with get division by zero .. squaroot of negative number,log of zero e.t.c
A) p(x)/m(x)= 1/squaroot(x) ÷ x²-4 which we know that x²-4 must not be equal to zero
because if is equal to zero we will have division by zero, which have contradicted the hypothesis of law of domain
x²-4 =! 0
(x-2)(x+2)=!0
x=!2 or x=!-2 because if is equal to that it's has contradicted d hypothesis
the answer is all real number except -2 and -
2
B)p(m(x))=p(x²-4) =1/squaroot of x²-4
note they are two things involve we must not get division by zero and root of negative number
we have all real number expect from -2 to 2
C)m(p(x))=m(1/root of (x))=(1/root of (x))²_4)
we have 1/x-4
so the answer is all real number expect zero