Question

What is the point-slope form of a line with slope 4/5 that contains the point (-2,1)?

Answer 1

Answer:
`\Large\boxed{y-1=(4)/(5) (x+2)}`

Explanation:

Given the requirement for function

Point-slope form : y - y₁ = m (x - x₁)

• m = slope
• (x₁, y₁) = Any points on the line

Given information

m = 4/5

Point = (x₁, y₁) = (-2, 1)

Substitute values into the function form

y - y₁ = m (x - x₁)

y - (1) = (4/5) (x - (-2))

Simplify the function

`\Large\boxed{y-1=(4)/(5) (x+2)}`

Hope this helps!! :)

Please let me know if you have any questions