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Use substitution to solve the system 3x+8y = -56 2x-y = 7

User Pkrish
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1 Answer

3 votes

Answer: x = 0 ; y = -7

Explanation:

Given equation:

1) 3x + 8y = -56

2) 2x - y = 7

Subtract 2x on both sides of 2) equation to isolate y-value

2x - y - 2x = 7 -2x

-y = 7 - 2x

Divide -1 on both sides of 2) equation

-y / -1 = (7 - 2x) / -1

y = 2x - 7

Current system

1) 3x + 8y = -56

2) y = 2x - 7

Substitute 2) equation into the y-value of 1) equation

3x + 8 (2x - 7) = -56

Simplify by distributive property

3x + 8 × 2x - 8 × 7 = -56

3x + 16x - 56 = -56

Combine like terms

19x - 56 = -56

Add 56 on both sides

19x - 56 + 56 = -56 + 56

19x = 0

Divide 19 on both sides

19x / 19 = 0 / 19


\Large\boxed{x=0}

Substitute the x-value into one of the equations to find the y-value

2x - y = 7

2 (0) - y = 7

0 - y = 7

-y = 7


\Large\boxed{y=-7}

Hope this helps!! :)

Please let me know if you have any questions

User Daniel Amarante
by
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