Question

A scientist observes light from a star with a wavelength 1 of 97 nanometers (9.7 x 108 m). What is the photon energy, E, of this light?

Use this information to help you:
v=£
speed of light in a vacuum, c = 3.00 x 108 meters/second
• Planck's constant, h = 4.136 × 10-15 ev-s
energy of the photon =

Answer 1

1.28 x 10⁻¹⁵ eV

Step-by-step explanation:

To find the energy, you can use the photon energy equation:

E = hc / λ

In this equation,

-----> E = energy (eV)

-----> h = Plank's Constant (4.136 x 10⁻¹⁵ eV*s)

-----> c = speed of light (3.00 x 10⁸ m/s)

-----> λ = wavelength (m)

You can find the energy of the photon by plugging the given values into the equation and solving.

E = hc / λ

E = (4.136 x 10⁻¹⁵ eV*s)(3.00 x 10⁸ m/s) / 9.7 x 10⁸ m

E = 1.2408 x 10⁻⁶ / 9.7 x 10⁸ m

E = 1.28 x 10⁻¹⁵ eV