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What is the [OH-] if the [H3O+] is 1 x 10 -10?

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The answer is [OH⁻] = 1 x 10⁻⁴.

[OH⁻] = H₂O ÷ [H₃O⁺]

[OH⁻] = 1 x 10⁻¹⁴ / 1 x 10⁻¹⁰

[OH⁻] = 10⁻⁴

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