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Given the following equation:

Mg(OH)2 + 2HCI --> MgCl2 + 2H₂O
How many moles of water form from one gram of magnesium hydroxide?
26
58
0.03
116
Question 5 (1 noint)
:

1 Answer

2 votes

Answer:

0.084 moles of H₂O

Step-by-step explanation:

RAM of Mg = 24, of H = 1, of O = 16

Mg(OH)₂ + 2HCI --> MgCl2 + 2H₂O

Mole of Mg(OH)₂ = mass/MolarMass

= 1/24 = 0.042mol

From the equation,

1 mole of Mg(OH)₂ = 2 moles of H₂O

0.042mol of Mg(OH)₂ = 2 × 0.042 of H₂O

= 0.084 moles of H₂O

User Belvi Nosakhare
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