Question

Help solve the question please.

Answer 1

Explanation:

Multiply both sides of the equation by
`b + √(2\\u)` to get

`cb + c√(2\\u) = a`

Put the cb term to the right hand side and then divide by c to get

`√(2\\u) = (a - cb)/(c)`

Taking the square of the equation, we get

`2\\u = \left((a - cb)/(c)\right)^2`

Finally, dividing the equation by 2 and we get an equation for
`\\u.`

`\\u = (1)/(2)\left((a - cb)/(c)\right)^2`

Answer 2

`v = \sqrt{(a -cb)/(c√(2)) } = \frac{√( a -cb)}{√(c)\sqrt[4]{2} }`

Explanation:

`c = (a)/(b+√(2v) )`

The equation for
`v` will be

`c = (a)/(b+√(2v) ) \implies c(b+√(2v)) = a \implies cb + c√(2v) = a`

Once
`√(2v) = √(2) √(v)`

`cb + c√(2)√(v) = a \implies c√(2)√(v) = a -cb \implies √(v) =(a -cb)/(c√(2))`

Square both sides

`√(v) =(a -cb)/(c√(2)) \implies v = \sqrt{(a -cb)/(c√(2)) } = \frac{√( a -cb)}{√(c)\sqrt[4]{2} }`