Question

5​(x−3​)−6x≥−3

Please don’t take it down just solve for x

Answer 1

Given :

`5(x−3)−6x≥−3`

Now opening brackets,

`5x - 15 - 6x \geqslant - 3`

`= > (5 - 6)x - 15 \geqslant - 3`

`= > - x - 15 \geqslant - 3`

`= > - x \geqslant - 3 + 15`

`= > - x \geqslant (15 - 3)`

`= > - x \geqslant 12`

`= > x \leqslant - 12`

Hence the answer is
`x \leqslant - 12`