391,414 views
22 votes
22 votes
I need help ASAP plzzzz

I need help ASAP plzzzz-example-1
User Benjamin Cremer
by
2.8k points

1 Answer

19 votes
19 votes

Answer:

a) 1.75s b) 17.2 m/s (down)

Step-by-step explanation:

d1= 15m d2= 0m (because it hits ground)

a= -9.81 m/s^2 t=???

Equation

the triangle means change in so d2-d1

Δd= v1 * t + 1/2 * a * t^2

0m-15m= v1*t + 1/2 a t^2

-15 m= 0m/s*t (goes away) + 1/2* a *t^2

-15mx2= t^2

-15mx2/a= t^2

Square root (-30/-9.81m/s^2)

t=1.75 s

b) now v2!!

Im going to use v2= v1 + a*t

v2= 0m/s + -9.81 x 1.75s

v2 = -17.2 m/s or you can say 17.2 m/s down!!!

User Ganjim
by
3.3k points