Question

The sum of the roots of the quadratic equation x^2 + 1=0 is equal to

Answer 1

x² + 1 = 0

a = 1

b = 0

c = 1

`x1.2 = \frac{ - b± \sqrt{ {b}^(2) - 4ac } }{2a}`

`x1.2 = \frac{ - 0 ±\sqrt{ {0}^(2) - (4.1.1) } }{2.1}`

`x1.2 = (0± √(0 - 4) )/(2)`

`x1.2 = (± √( - 4) )/(2)`

There is no real solution because the discriminant is negative

Note.

Formula diskriminan

√b² - 4ac.

if the diskrimanan is negatif, so the quadratic equatoin dont have solution