so
Or
Option A
Explanation:
|y – 3| − 4 ≤ −3
|y – 3| ≤ -3+4
|y – 3| ≤ 1
-1 ≤ y-3 ≤ 1
=> -1 ≤ y - 3 or y - 3 ≤ 1 (the first option)
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