Answer:
4,28
Explanation:
So let's look at the sentence to take any necessary information out. It says the length of a rectangle plus it's width is 32. Since we do not know what the length and width are, let's just represent them as L (length) and W (width). Using this information we get the equation:
and since we're given the area of the rectangle, we can also define another equation which is:
since the length * width = area.
So now all we have is a systems of equations. We can solve for L or W in the area equation and plug it into the addition equation. We can also solve for L or W in the addition equation and then plug it into the area equation, either should work, but in this example I'll solve for L in the addition equation:
Original Equation:
![L + W = 32](https://img.qammunity.org/2023/formulas/mathematics/high-school/1i8ybbe6ebmm0er8wt5vs2s5r7f6poohhu.png)
Subtract 32 from both sides
![L = 32-W](https://img.qammunity.org/2023/formulas/mathematics/high-school/1eq6arq6axn5z8f40cjhtjmw8bcakbhjds.png)
Now let's use this definition of L to plug into the second equation:
![LW = 112 \implies (32-W)W = 112](https://img.qammunity.org/2023/formulas/mathematics/high-school/1sgjbksbmw8sbty7pq7h74qgcrag4gbouw.png)
Distribute the W
![-W^2+32W=112](https://img.qammunity.org/2023/formulas/mathematics/high-school/dxii1ht0dq7aiwzwov45ptcbfdnb6l9m1i.png)
Now if you notice, we simply have a quadratic equation and we can subtract 112 from both sides and then use the quadratic formula:
![x=(-b\pm√(b^2-4ac))/(2a)](https://img.qammunity.org/2023/formulas/mathematics/college/jr19ixi2zltkocy82qhxfiop5lyv4hzbkm.png)
Subtract 112 from both sides
![-W^2+32W-112=0](https://img.qammunity.org/2023/formulas/mathematics/high-school/bo2e2uq0lf0d9rrymsd55hny16v44tli1f.png)
Use quadratic formula
![W = (-32\pm√(32^2-4(-1)(-112)))/(2(-1))](https://img.qammunity.org/2023/formulas/mathematics/high-school/emigfod3f7ra95796rdybdq86u9vuzlenb.png)
Simplify stuff in radical
![W = (-32\pm√(576))/(-2)](https://img.qammunity.org/2023/formulas/mathematics/high-school/qc8mge2zb9jwdgd9gr9wv857irro8vntyz.png)
Calculate the square root
![W=(-32\pm24)/(-2)](https://img.qammunity.org/2023/formulas/mathematics/high-school/4kii5y36u8bt6wfwlcu5rzq8cnfr9ziax7.png)
Use positive sign:
![W=(-32+24)/(-2)](https://img.qammunity.org/2023/formulas/mathematics/high-school/8m78wgjon9giil0q1xg4ftsneh214h4ba2.png)
Simplify numerator
![W = (-8)/(-2)](https://img.qammunity.org/2023/formulas/mathematics/high-school/zrjd4pg87bbjo0vpz0vze4q5mnl2l1c5tn.png)
Simplify fraction
![W=4](https://img.qammunity.org/2023/formulas/mathematics/high-school/xhv8143jm6x2qpsp8eqt3sp9il03gh4adu.png)
Take negative sign
![W = (-32-24)/(-2)](https://img.qammunity.org/2023/formulas/mathematics/high-school/i0kpspj6ungwos4j5rl6zvj6zhg7d07g3z.png)
Simplify numerator
![W=(-56)/(-2)](https://img.qammunity.org/2023/formulas/mathematics/high-school/q5v1dpry6vchbvkdzhb55e7cy0hsvlwp2v.png)
W =
![28](https://img.qammunity.org/2023/formulas/mathematics/college/4phlo317m4wgnvw85y3b0w3pwnuvdh64cz.png)
So we have two solutions, and the reason for this is because had we solved for W in the original equation and substituted that into here, there would be no different, it's not bound by some variable name. So these are actually the two sides of the rectangles
4 + 28 = 32
4 * 28 = 112
4, 28