The answer is y = -6x + 15/2.
First, find the slope of BC.
m = Δy/Δx
m = 2 - 1 / 4 - (-2)
m = 1/6
Hence, the slope of the perpendicular bisector will be the negative reciprocal of the given line.
m' = - (1/ [1/6])
m' = -6
Now, find the midpoint of BC.
M = (-2 + 4 / 2, 2 + 1 / 2)
M = (1, 3/2)
Now, we can find the equation of the perpendicular bisector using the point slope form of equation.
y - y₁ = m (x - x₁)
y - 3/2 = -6 (x - 1)
y - 3/2 = -6x + 6
y = -6x + 15/2