358,404 views
18 votes
18 votes
Solve the equation y^2-y-5=-3

User MichaelA
by
3.0k points

1 Answer

12 votes
12 votes

Answer:


= y_(1) = - 1 \: . \: \: y_(2) = 2

Explanation:


{y}^(2) - y - 5 = - 3 \\ {y}^(2) - y - 5 + 3 = 0 \\ {y}^(2) + y - 2y - 2 = 0 \\ y(y + 1) - 2(y + 1) = 0 \\ (y + 1)(y - 2) = 0 \\ y + 1 = 0 \\ y - 2 = 0 \\ y = - 1 \\ y = 2


\boxed{\green{= y_(1) = - 1 \: . \: \: y_(2) = 2}}

User Ricky Nelson
by
3.4k points
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