Question

Given the functions a(x) = 3x - 12 and b(x) = x-9, solve a[b(x)].

Oa[b(x)] = 3x²-21

O a[b(x)] = 3x² - 39

Oa[b(x)] = 3x - 21

Oa[b(x)] = 3x - 39

Answer 1

Explanation:

hello :

a(x) = 3x - 12 and b(x) = x-9, so

a[b(x)]=a(x-9) =3(x-9)-12

a[b(x)]=3x-9-12

a[b(x)]=3x+21