Question

PLEASE HELP!!!!

Cooling towers are used to remove or expel heat from a process. A cooling tower's walls are modeled by x squared over 400 minus quantity y minus 110 end quantity squared over 2304 equals 1 comma where the measurements are in meters. What is the width of the cooling tower at the base of the structure? Round your answer to the nearest whole number.

100 meters
50 meters
48 meters
40 meters

Answer 1

(a) 100 meters

Explanation:

You want the width at the base of a cooling tower whose walls are modeled by the equation (x/20)² -((y-110)/48)² = 1.

Base

The width at the base will be the difference in the values of x when y=0.

(x/20)² -((0 -110)/48)² = 1

(x/20)² = 1 +3025/576

x = ±20/24√3601 ≈ ±50.01

The width will be 50.01 -(-50.01) ≈ 100 meters.

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