Question

Using the quadratic formula, solve the

equation below to find the two possible
values of t.
6x^2-35=-11x
Give each value as a fraction in its
simplest form.

Answer 1

x= 19/12, -41/12

Explanation:

I'm guessing x is "t".

The quadratic formula is x=(-b+-sqrtb^2-4ac)/2a I know that this is hard to read sorry!

Plug in a, b, and c.

Oh yeah, first convert it to the form Ax^2+bx+c

so 6x^2-35=-11x

6x^2+11x-35=0

(-11+-sqrt11^2-(-4*6*35))/2*6

Simply: (-11+-sqrt 121+840)/12

(-11+-sqrt961)/12

(-11+-31)/12

-11+30=19

-11-30=-41

x= 19/12, -41/12