Question

A sample of an unknown substance has a mass of 0. 465 kg. If 3,000. 0 j of heat is required to heat the substance from 50. 0°c to 100. 0°c, what is the specific heat of the substance? use q equals m c subscript p delta t.

Answer 1

.129 J / g-C

Step-by-step explanation:

specific heat = J / g-°C

= 3000 J / ( 465 g * 50C ) =.129 J /g-C