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7. A movable piston is allowed to cool from 392°F to 104°F. If the initial volume is 105 mL,

what will be the new volume?

User Ujjual
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1 Answer

2 votes

Answer:

27.9 mL

Step-by-step explanation:

To find the new volume, you need to use the Charles' Law equation:

V₁ / T₁ = V₂ / T₂

In this equation, "V₁" and "T₁" represent the initial volume and temperature. "V₂" and "T₂" represent the final volume and temperature.

V₁ = 105 mL V₂ = ? mL

T₁ = 392 °F T₂ = 104 °F

V₁ / T₁ = V₂ / T₂ <----- Charles' Law

105 mL / 392 °F = V₂ / 104 °F <----- Insert values

0.26785 = V₂ / 104 °F <----- Simplify left side

27.9 = V₂ <----- Multiply both sides by 104

User Aaron Shen
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