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Sin^6 theta - cos^6 theta = ( 1-2cos^2 theta) (1- sin^2 theta .cos^2 theta )​
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Sin^6 theta - cos^6 theta = ( 1-2cos^2 theta) (1- sin^2 theta .cos^2 theta )​

User Donkim
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Please find attached herewith the solution of your question.

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Sin^6 theta - cos^6 theta = ( 1-2cos^2 theta) (1- sin^2 theta .cos^2 theta )​-example-1
User Maksim Nikolaev
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