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Please help me with this Pythagoras theorem..

A triangle DEF is right- angled at E, with DE=6.7m and EF=5.5m . find the length of DF. ​

Please help me with this Pythagoras theorem.. A triangle DEF is right- angled at E-example-1
User Shadowman
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2 Answers

14 votes
14 votes

Answer:

8.7m

Explanation:

[6.7]²+5.5}²

=[75.14]

√75.14m

=8.7m

User Gravy
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2.1k points
14 votes
14 votes

Explanation:


{(df)}^(2) = {(de)}^(2) + {(ef)}^(2) \\ = {6.7}^(2) + {5.5}^(2) \\ = 44.89 + 30.25 \\ = 75.14 \\ df = √(75.14) = 8.67m \\ thank \: you

User Chris Putnam
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2.7k points