Lim x tends to a now find x^1/3-a^1/3/x^1/2-a^1/2

Keivan Esbati asked Sep 14, 2022

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Keivan Esbati asked Sep 14, 2022

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25 votes

Answer:
(a)/(3)-(2)/(3)-(a)/(2)

Explanation:

$\lim _(x\to \:a)\left((x^1)/(3)-((a^1)/(3))/((x^1)/(2))-(a^1)/(2)\right)$

=(a^1)/(3)-((a^1)/(3))/((a^1)/(2))-(a^1)/(2)

=(a)/(3)-(2)/(3)-(a)/(2)

Washingon answered Sep 20, 2022

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