Answer:
The two answers:
2.707778736
0.42206445
Explanation:
Here is the equation:
![{7x}^(2) - 16x = 8](https://img.qammunity.org/2023/formulas/mathematics/high-school/lu07m15zioh47t6kba557lbec7sj554qge.png)
Take away the 8 from the right hand side, so that we are left with this quadratic equation:
![{7x}^(2) - 16x - 8 = 0](https://img.qammunity.org/2023/formulas/mathematics/high-school/is8lag26txpgikbctycmvrgxeys1olu5fw.png)
This equation is too complex to solve with the factorizing method, so let's use the quadratic formula, which is as follows:
![x = (-b \pm √(b^2 - 4ac))/(2a)](https://img.qammunity.org/2023/formulas/mathematics/college/gugtdmmdy3dq08m3vfhq51kdcailqcwa0k.png)
In this equation, a = 7, b = -16, and c = -8. So let's substitute in:
![x = \frac{-( - 16) \pm \sqrt{ { - 16}^(2) - 4 * 7 * - 8}}{2 * 7}](https://img.qammunity.org/2023/formulas/mathematics/high-school/7oxqb6l6zoh4y71mq7q9zrggzjpl6u5qou.png)
![x = ( - ( - 16) \pm √(256 + 224) )/(14)](https://img.qammunity.org/2023/formulas/mathematics/high-school/wn7yni0fd0gj9weskm5iw51wfex4t07th5.png)
![x = ( 16 \pm √(480))/(14)](https://img.qammunity.org/2023/formulas/mathematics/high-school/g0oxgcz2x15mpl43pg83j48f0rz5gza2pu.png)
And let's work out the two possible answers:.
2.707778736
0.42206445