Question

The sum of three numbers is 131. the second of three numbers is seven more than twice the first. the third number is 12 less than the first. what equation can be used to solve the problem? x x x = 131 x (x 7) (x – 12) = 131 x (2x 7) (x – 12) = 131 x (2x 7) – 12 = 131

Answer 1

• C. x + (2x + 7) + (x - 12) = 131

Explanation:

Let the first number be x.

Then, given:

• The second number is 2x + 7
• The third number is x - 12

Since their sum is 131, we get the following equation:

• Sum of x, (2x + 7) and (x - 12) is 131,

or

• x + (2x + 7) + (x - 12) = 131

This is matching the answer choice C.